Calculate the mass of ice required to lower the temperature of 300g

Heat (10)

Calculate the mass of ice required to lower the temperature of 300g of water at 40°C to water at 0°C.

(Specific latent heat of ice=336 J/g, Specific heat capacity of water=4.2 J/g^oC)

Answer

𝑚 × 336 = 300 × 4.2 × 40

m = 300 × 4.2 × 40/ 336

=150 g