The volume occupied by 80 g of carbon dioxide at STP
Mole Concept (10)Calculate: The volume occupied by 80 g of carbon dioxide at STP.
Answer
44 g of carbon dioxide occupies 22.4 L or 22400 mL
80 g of carbon dioxide occupies = (80 x 22.4)/44 = 40.72 L
Or (80 x 22400)/44 = 40720 mL
- Exam Year: 2020